Question

Algebra 395 misol 1)×⁴-5ײ+4=0; 2)×⁴-8ײ-9=0

Answer 1

Пошаговое объяснение:

вроде все понятно,если условия не пишите,то е пишите,что логично.

Answer 2

To solve the given quadratic equations, let's denote the variable as "x" and solve them one by one:

1. x⁴ - 5x² + 4 = 0

Let's substitute y = x²:

y² - 5y + 4 = 0

Now we can factorize this quadratic equation:

(y - 4)(y - 1) = 0

Setting each factor to zero, we have:

y - 4 = 0 or y - 1 = 0

Solving for y in each case:

y = 4 or y = 1

Substituting y back in terms of x:

For y = 4: x² = 4 x = ±√4 x = ±2

For y = 1: x² = 1 x = ±√1 x = ±1

Therefore, the solutions to the equation x⁴ - 5x² + 4 = 0 are x = ±2 and x = ±1.

2. x⁴ - 8x² - 9 = 0

Let's substitute y = x²:

y² - 8y - 9 = 0

Now we can factorize this quadratic equation:

(y - 9)(y + 1) = 0

Setting each factor to zero, we have:

y - 9 = 0 or y + 1 = 0

Solving for y in each case:

y = 9 or y = -1

Substituting y back in terms of x:

For y = 9: x² = 9 x = ±√9 x = ±3

For y = -1: x² = -1 (No real solutions)

Therefore, the solutions to the equation x⁴ - 8x² - 9 = 0 are x = ±3.