Question

-sin30° + cos30° – ctg30° + tg30​

Answer 1

Ответ:

-1/2-√3/6

Пошаговое объяснение:

-1/2+√3/2-√3+√3/3=-1/2-√3/6

Answer 2

-

$- \frac{1}{2} + \frac{ \sqrt{3} }{2} - \sqrt{3} + \frac{1}{ \sqrt{3} }$

$1) \: \frac{ \sqrt{3} }{2} - \sqrt{3} \: + \frac{ \sqrt{3} }{ \sqrt{3} }$

Избавляемся от инерциальности. Вычисляем разницу первого выражения.

$2) \: - \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{ \sqrt{3} } = \: - \frac{ \sqrt{3} }{6}$

$3) \: - \frac{1}{2} - \frac{ \sqrt{3} }{6} = - 0.78$

Ответ: -0.78

Answer 3

To evaluate the expression, let's calculate the values of each trigonometric function at the given angles:

sin(30°) = 0.5 cos(30°) = √3/2 ≈ 0.866 cot(30°) = 1/tan(30°) = 1/√3 ≈ 0.577 tan(30°) = sin(30°)/cos(30°) = 0.5 / (√3/2) = √3/3 ≈ 0.577

Now we can substitute these values into the expression:

-sin(30°) + cos(30°) - cot(30°) + tan(30°) = -0.5 + 0.866 - 0.577 + 0.577 = 0.866 - 0.5 - 0.577 + 0.577 = 0.366

Therefore, the value of the expression -sin30° + cos30° – ctg30° + tg30​ is approximately 0.366.