Question

(3/4+1/20)*1/2=(7/12-1/3)*16/19=Заранее спасибо ​

Answer 1

Ответ:

$1.( \frac{3}{4} + \frac{1}{20} ) \times \frac{1}{2} = \frac{4}{5} \times \frac{1}{2} = \frac{2}{5}$

$2.( \frac{7}{12} - \frac{1}{3} ) \times \frac{16}{19} = \frac{1}{4} \times \frac{16}{19} = \frac{4}{19}$

Answer 2

To solve the given equations, let's break it down step by step:

Equation 1: (3/4 + 1/20) * 1/2

First, let's simplify the addition inside the parentheses: 3/4 + 1/20 = (15/20 + 1/20) = 16/20

Now, multiply the result by 1/2: (16/20) * (1/2) = (16 * 1) / (20 * 2) = 16/40 = 4/10 = 2/5

So, the result of the first equation is 2/5.

Equation 2: (7/12 - 1/3) * (16/19)

First, let's simplify the subtraction inside the parentheses: 7/12 - 1/3 = (7/12 - 4/12) = 3/12 = 1/4

Now, multiply the result by 16/19: (1/4) * (16/19) = (1 * 16) / (4 * 19) = 16/76 = 4/19

So, the result of the second equation is 4/19.

Therefore, the solutions are:

(3/4 + 1/20) * 1/2 = 2/5 (7/12 - 1/3) * (16/19) = 4/19

You're welcome!