Question

1. 1.2х=-3.6 A -2/3 2. 1/3х=-2/3 Б. -1/2 3. -2 2/3x=1 1/3 В. -0.2 4.-2 1/3x=7/15 Г. 3 Д. 1/3 СРООООЧНООО БУУУДЬ ЛАСКА ДАЮ 15 БАЛІВ СРОООООООООООООООООЧНОООООООООООООООО

Answer 1

Ответ: 1)-3 ; 2)-2;  3)-1/2; 4)-1/5 или -0,2

Пошаговое объяснение:

1. 1.2х=-3.6

x=-3,6:1,2

x=-3

Проверка

1.2*(-3)=-3.6

2. 1/3х=-2/3

x=-2/3:1/3

х=-2/3*3/1

х=-2

Проверка

1/3*(-2)=-2/3

3. -2 2/3x=1 1/3

х=4/3:(-8/3)

х=-4/3*3/8

х=-4/8=-1/2

Проверка

. -2 2/3*(-1/2)=-8/3*(-1/2)=8/6=1  1/3

4.-2 1/3x=7/15

-7/3х=7/15

х=7/15:(-7/3)

х=-7/15*3/7

х=-3/15=-1/5 или -0,2

Проверка

-2 1/3*(-1/5)=-7/3*(-1/5)=7/15

Answer 2

1. To solve the equation 1.2x = -3.6 - (2/3), we can simplify the right side first:

-3.6 - (2/3) = -3.6 - (2/3) = -3.6 - 0.666... = -4.266...

Now we can solve the equation:

1.2x = -4.266...

To isolate x, we divide both sides of the equation by 1.2:

x = (-4.266...)/1.2

The exact value of x would be a recurring decimal, but to approximate it, we can calculate:

x ≈ -3.5556

2. To solve the equation (1/3)x = -2/3 - (1/2), we can simplify the right side first:

-2/3 - (1/2) = -2/3 - 3/6 = -2/3 - 1/2 = -4/6 - 3/6 = -7/6

Now we can solve the equation:

(1/3)x = -7/6

To isolate x, we multiply both sides of the equation by 3:

x = (-7/6) * 3

x = -21/6

Simplifying the fraction, we get:

x = -7/2

3. To solve the equation (-2 2/3)x = 1 1/3, we can convert the mixed numbers to improper fractions:

(-2 2/3)x = (3 * -2 + 2)/3 = (-6 + 2)/3 = -4/3

Now we can solve the equation:

(-4/3)x = 1 1/3

To isolate x, we multiply both sides of the equation by -3/4:

x = (1 1/3) * (-3/4)

x = (4/3) * (-3/4)

x = -1

4. To solve the equation (-2 1/3)x = 7/15, we can convert the mixed number to an improper fraction:

(-2 1/3)x = (3 * -2 + 1)/3 = (-6 + 1)/3 = -5/3

Now we can solve the equation:

(-5/3)x = 7/15

To isolate x, we multiply both sides of the equation by -3/5:

x = (7/15) * (-3/5)

x = (-21/75)

Simplifying the fraction, we get:

x = -7/25

Please note that these calculations are approximate values, and the exact values might involve recurring decimals or fractions.