Question

1) |2x +1 < 3; 2) 1-2x < 5; 3) 3x-27; 4) 4+ 3x > 2; 5) |5x+3 5.​

Answer 1

1)2х<3-1 2)2х<5+1 3)х=27:3

2х<2 2х<6 х=9

х<2:2 х<6:2

х<1 х<3

4)3х>4-2 х=5:3,5

3х>2 х=1,4

х>3:2

х>1,5

Answer 2

Ответ:

ответы на фотках выше. 3 задание не полное

Answer 3

It seems that some of the expressions you provided are incomplete or contain errors. I'll do my best to interpret and solve them for you:

1. |2x + 1| < 3: To solve this absolute value inequality, we need to consider two cases: when the expression inside the absolute value is positive and when it is negative.

Case 1: 2x + 1 > 0 (when the expression inside the absolute value is positive) In this case, the inequality becomes: 2x + 1 < 3 2x < 3 - 1 2x < 2 x < 1

Case 2: 2x + 1 < 0 (when the expression inside the absolute value is negative) In this case, we need to negate the inequality when we remove the absolute value. So the inequality becomes: -(2x + 1) < 3 -2x - 1 < 3 -2x < 3 + 1 -2x < 4 x > -2 (we also flipped the inequality when dividing by a negative number)

Therefore, the solution to the inequality |2x + 1| < 3 is -2 < x < 1.

2. 1 - 2x < 5: To solve this linear inequality, we isolate the variable x: -2x < 5 - 1 -2x < 4 Dividing both sides by -2, we must reverse the inequality: x > 4/(-2) x > -2

So the solution to the inequality 1 - 2x < 5 is x > -2.

3. 3x - 27: The expression 3x - 27 seems incomplete. If you intended to write an equation or inequality, please provide the complete expression so that I can assist you further.

4. 4 + 3x > 2: To solve this linear inequality, we isolate the variable x: 3x > 2 - 4 3x > -2 Dividing both sides by 3, we get: x > -2/3

So the solution to the inequality 4 + 3x > 2 is x > -2/3.

5. |5x + 3| 5: The expression |5x + 3| 5 appears to have a missing comparison operator. If you can clarify the intended inequality or provide additional information, I'll be able to assist you better.