Question

-2tg(2pi+a)+3tg(-a), tga=0.7

Answer 1

Ответ:

-2tg(a)+3(-tg(a))=-2tg(a)-3tg(a)=(-2-3)tg(a)=-5tg(a)

-5*0.7=-3.5

Пошаговое объяснение:

Answer 2

To solve this expression, we can start by using the trigonometric identity:

tg(-a) = -tg(a)

So, we can rewrite the expression as:

-2tg(2π+a) + 3tg(a) = -2tg(2π+a) + 3(-tg(-a)) = -2tg(2π+a) - 3tg(a)

Now, we can substitute the value of tga = 0.7 into the expression:

-2tg(2π+a) - 3tg(a) = -2tg(2π+arctan(0.7)) - 3(0.7)

We can use the following trigonometric identity to simplify tg(2π+arctan(0.7)):

tg(2π+θ) = tg(θ)

where θ is any angle. So,

tg(2π+arctan(0.7)) = tg(arctan(0.7)) = 0.7/√(1+0.7^2)

Substituting this value into the expression, we get:

-2tg(2π+a) - 3tg(a) = -2(0.7/√(1+0.7^2)) - 2.1

Simplifying this expression, we get:

-2tg(2π+a) - 3tg(a) ≈ -4.121

Therefore, the value of the expression is approximately -4.121.