Question

Упростите выражения:2\3c+1\9c-7\9c k-1/7k 3\11y+8\11y 3\5b+b

Answer 1

2/3с + 1/9с - 7/9с = 6/9с + 1/9с - 7/9с = 0с =
k - 1/7k = 7/7k - 1/7k = 6/7k
3/11у + 8/11у = 11/11у = 1у = у
3/5b + b = 3/5b + 1b = 1целая 3/5b

Answer 2

1) 2/3с + 1/9с - 7/9с = 6/9с+1/9с-7/9с=0/9с=0
2) к-1/7к=7/7к-1/7к=6/7к
3) 3/11у+8/11у=11/11у=у
4) 3/5в+в=3/5в+5/5в=8/5в=1целая 3/5в

Answer 3

1. $2/3c + 1/9c - 7/9c$ To simplify this expression, we need to first find a common denominator, which is 9c. Then, we can combine the fractions:

$2/3c + 1/9c - 7/9c = (6/9)c + (1/9)c - (7/9)c = 0$

Therefore, the simplified expression is just 0.

2. $k - 1/7k$ We can simplify this expression by finding a common denominator, which is 7k. Then, we can combine the fractions:

$k - 1/7k = (7k/7k) - (1/7k) = (7k - 1)/7k$

Therefore, the simplified expression is $(7k - 1)/7k$.

3. $3/11y + 8/11y$ We can combine these fractions since they have the same denominator:

$3/11y + 8/11y = (3+8)/11y = 11/11y = 1/y$

Therefore, the simplified expression is $1/y$.

4. $3/5b + b$ We cannot combine these two terms since they do not have the same denominator. However, we can rewrite $b$ as a fraction with a denominator of 5b:

$3/5b + b = 3/5b + 5b/5b = (3+5b)/5b$

Therefore, the simplified expression is $(3+5b)/5b$.