Question

-0,2х^2+45=0 .......

Answer 1

-0.2x^2+45=0
-0.2x^2=-45
x^2=-45:(-0.2)
x^2=225
x=√ ±225
x= ±15

$\left \{ {{x=15} \atop {x=-15}} \right.$

x∈(-15;15)

Answer 2

To solve the equation -0.2x^2 + 45 = 0, you can follow these steps:

1. Subtract 45 from both sides of the equation: -0.2x^2 = -45

2. Divide both sides of the equation by -0.2: x^2 = 225

3. Take the square root of both sides of the equation, remembering to include both the positive and negative square roots: x = ±15

Therefore, the solutions to the equation -0.2x^2 + 45 = 0 are x = 15 and x = -15.