Question

Найти y' y=6x^3+8x^2-3x

Answer 1

Y'=6*3x²+8*2x-3=18x²+16x-3

Answer 2

To find the derivative y' of the function y=6x^3+8x^2-3x, we need to use the power rule and the sum rule of differentiation:

Power rule: If y = x^n, then y' = nx^(n-1). Sum rule: If y = u + v, then y' = u' + v'.

Using the power rule, we can find the derivatives of the three terms in the function:

y = 6x^3 + 8x^2 - 3x y' = (63)x^(3-1) + (82)x^(2-1) - 3 y' = 18x^2 + 16x - 3

Therefore, the derivative of y=6x^3+8x^2-3x is y' = 18x^2 + 16x - 3.