Question

(a-3)^2+(a-3)(a+3)+6a Помогите

Answer 1

= a^2 - 6a +9 +a^2 + 3a - 3a - 9 +6a =2a^2

Answer 2

Sure! Let's simplify the expression step by step:

1. Start by expanding the square term: (a-3)^2 = (a-3)(a-3) = a^2 - 6a + 9

2. Expand the second term using the distributive property: (a-3)(a+3) = a^2 - 9

3. Add the two expanded terms together: (a-3)^2 + (a-3)(a+3) = a^2 - 6a + 9 + a^2 - 9 = 2a^2 - 6a

4. Add the third term: (a-3)^2 + (a-3)(a+3) + 6a = 2a^2 - 6a + 6a = 2a^2

Therefore, the simplified expression is 2a^2.