Question

X^2+4x+5=0 3x^2-8x+13=0 5x^2-12x+9=0

Answer 1

1)х^2+4х+5=0
D= 4^2-4×1×5=16-20= -4 нет решения, т. к D не может быть числом отрицательным
2)3х^2-8х+13=0
D=(-8)^2 -4×3×13=64-156=-92 нет решения
3)5х^2-12х+9=0
D=(-12)^2-4×5×9=144-180=-36 нет решения

Answer 2

Вот так решается надеюсь правильно

Answer 3

To solve these equations for x, we can use the quadratic formula:

For the equation ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

Using this formula, we can solve each of the equations you provided:

1. X^2+4x+5=0: a = 1, b = 4, c = 5 x = (-4 ± sqrt(4^2 - 4(1)(5))) / 2(1) x = (-4 ± sqrt(-4)) / 2 x = (-4 ± 2i) / 2 x = -2 ± i

Therefore, the solutions to X^2+4x+5=0 are x = -2 + i and x = -2 - i.

2. 3x^2-8x+13=0: a = 3, b = -8, c = 13 x = (8 ± sqrt(8^2 - 4(3)(13))) / 2(3) x = (8 ± sqrt(-44)) / 6 x = (8 ± 2isqrt(11)) / 6 x = (4 ± isqrt(11)) / 3

Therefore, the solutions to 3x^2-8x+13=0 are x = (4 + isqrt(11)) / 3 and x = (4 - isqrt(11)) / 3.

3. 5x^2-12x+9=0: a = 5, b = -12, c = 9 x = (12 ± sqrt(12^2 - 4(5)(9))) / 2(5) x = (12 ± sqrt(144 - 180)) / 10 x = (12 ± sqrt(-36)) / 10 x = (12 ± 6i) / 10 x = (6 ± 3i) / 5

Therefore, the solutions to 5x^2-12x+9=0 are x = (6 + 3i) / 5 and x = (6 - 3i) / 5.