Question

(5y+1)*(13y-4)=0 пжжжжжжжж

Answer 1

5y+1=0 или 13у-4=0

5у=-1            13у=4

у= -0,2          у=4/13

Ответ: -0,2 или 4/13

Answer 2

(5y+1)*(13y-4)=0

• 5y+1=9
• 5y+1=913y-4=0
• 5y+1=913y-4=0y^1=-1/5
• 5y+1=913y-4=0y^1=-1/5y^2=4/13

Answer 3

To solve the equation "(5y+1)*(13y-4)=0", we need to find the values of 'y' that make the equation true.

When we have a product equal to zero, it means that at least one of the factors must be zero. Therefore, we can set each factor equal to zero and solve for 'y'.

Setting the first factor equal to zero:

5y + 1 = 0

Subtracting 1 from both sides:

5y = -1

Dividing by 5:

y = -1/5

Setting the second factor equal to zero:

13y - 4 = 0

Adding 4 to both sides:

13y = 4

Dividing by 13:

y = 4/13

Therefore, the solutions to the equation (5y+1)*(13y-4)=0 are y = -1/5 and y = 4/13.