Question

(3b-4)^2-6b(b-4) при b= корень из 19

Answer 1

(3b-4)^2-6b(b-4)=9b^2-24b+16-6b^2+24b=3b^2+16

3*19+16=73
Ответ:73

Answer 2

To evaluate the expression (3b-4)^2-6b(b-4) when b is the square root of 19, we substitute the value of b into the expression and simplify it step by step.

Let's start by substituting b = √19 into the expression:

(3(√19)-4)^2 - 6(√19)(√19-4)

Simplifying further:

(3√19 - 4)^2 - 6(19 - 4√19)

Expanding the square:

(9√19 - 12√19 + 16) - 6(19 - 4√19)

Combining like terms:

9√19 - 12√19 + 16 - 114 + 24√19

Simplifying:

-3√19 + 2√19 + 16 - 114

Combining like terms:

-√19 + 16 - 98

Simplifying further:

-√19 - 82

So, when b is the square root of 19, the expression (3b-4)^2-6b(b-4) evaluates to -√19 - 82.