Question

3x-5x-15-x=1,8 |x|=2,4 |x-3|-2=3 |x-2|=0 3(2x-1)+7-5(2x-1)=5 x*(-7x-28)=0 Помогите пожалуйста!!!!

Answer 1

3х-5х-15-х=1,8
-3х=16,8
х=16,8:(-3)
х=5,6

|x|=2,4
х=2,4

|x-3|-2=3
|х-3|=5
х+3=5
х=2

|x-2|=0
х+2=0
х=-2

3(2x-1)+7-5(2x-1)=5
6х-3+7-10х-5=5
-4х-1=5
-4х=6
х=-4/6
х=-2/3

x*(-7x-28)=0
х1=0
-7х-28=0
-7х=28
х2=-4

Answer 2

1)-3х-15=1.8
-3х=15+1.8
-3х=16,8
х=-5.6
2)|х|=2.4
х=2.4 и х=-2.4
3)|х-3|-2=3
|х-3|=3+2
|х-3|=5
х-3=5 х-3=-5
х=8 х=-2
4)|х-2|=0
х-2=0
х=0
5)3(2х-1)+7-5 (2х-1)=5
3 (2х-1)-5 (2х-1)=5-7
(3-5)(2х-1)=5-7
-2(2х-1)=5-7
2х-1=1
2х=1+1
х=2
6)х (-7х-28)=0
х=0
-7х-28=0
х=0
х=-4

Answer 3

Let's solve each equation one by one:

1. 3x - 5x - 15 - x = 1.8

Simplifying the left side, we get:

-2x - 15 = 1.8

Adding 15 to both sides, we get:

-2x = 16.8

Dividing by -2, we get:

x = -8.4

Therefore, the solution is x = -8.4.

2. |x| = 2.4

Since the absolute value of x is equal to 2.4, x can be either 2.4 or -2.4.

Therefore, the solutions are x = 2.4 and x = -2.4.

3. |x - 3| - 2 = 3

Adding 2 to both sides, we get:

|x - 3| = 5

Since the absolute value of x - 3 is equal to 5, x can be either 8 or -2.

Therefore, the solutions are x = 8 and x = -2.

4. |x - 2| = 0

Since the absolute value of x - 2 is equal to 0, x must be equal to 2.

Therefore, the solution is x = 2.

5. 3(2x - 1) + 7 - 5(2x - 1) = 5

Simplifying the left side, we get:

6x - 3 + 7 - 10x + 5 = 5

Simplifying further, we get:

-4x + 9 = 5

Subtracting 9 from both sides, we get:

-4x = -4

Dividing by -4, we get:

x = 1

Therefore, the solution is x = 1.

6. x * (-7x - 28) = 0

This equation can be factored as:

x * (-7x - 28) = 0 x * -7(x + 4) = 0

Therefore, the solutions are x = 0 and x = -4.

I hope this helps! Let me know if you have any further questions.