Question

1)6!+60-x!=6!-60 2)g+3g-20=16 3)G!+(5g-5!)-g=48+400+32 Уравнения пж

Answer 1

1)x!=6!-6!+60=60

x!=120

x=5      (1*2*3*4*5=120)

2)4g=36

g=36/4

g=9

3)g!+4g - 120=48+400+32

g!+4g=600

В уравнении где есть факториал g принадлежит натуральным числам из определения факториала

Пусть g=5

140=600 - неверно

Пусть g=6

744=600 -неверно

Значит g может быть равно от 5 до 6 не включительно. Значит g не является натуральным числом поэтому уравнение не имеет решений

Answer 2

1. To solve the equation 6! + 60 - x! = 6! - 60, we can simplify the equation first.

Since 6! (6 factorial) is equal to 6 × 5 × 4 × 3 × 2 × 1 = 720, we can substitute it into the equation:

720 + 60 - x! = 720 - 60

Combine like terms:

780 - x! = 660

Now, subtract 780 from both sides to isolate the x! term:

-x! = -120

To solve for x, we need to find the factorial of a negative number, which is not defined. Therefore, there is no solution for this equation.

2. To solve the equation g + 3g - 20 = 16, we can combine like terms:

4g - 20 = 16

Next, add 20 to both sides to isolate the variable term:

4g = 36

Finally, divide both sides by 4 to solve for g:

g = 9

So, the solution to this equation is g = 9.

3. To solve the equation G! + (5g - 5!) - g = 48 + 400 + 32, we can simplify the equation.

Since the factorial symbol (!) applies to G, we'll assume that G is a positive integer.

First, calculate 5! (5 factorial):

5! = 5 × 4 × 3 × 2 × 1 = 120

Now, substitute the value of 5! into the equation:

G! + (5g - 120) - g = 48 + 400 + 32

Combine like terms:

G! + 4g - 120 = 480

Next, add 120 to both sides to isolate the G! term:

G! + 4g = 600

To solve this equation further, we need more information about the value of G or any additional constraints.