Question

(x-3)(x+3)=(2x-3)²-18​

Answer 1

(x-3)(x+3)=(2x-3)²-18

x^2-9 = 4x^2-12x+9-18

x^2=4x^2-12x

-3x^2×(x-4)=0

x=0;x=4

Answer 2

Let's solve the equation step by step.

Expanding the left side of the equation: (x - 3)(x + 3) = x^2 - 3x + 3x - 9 = x^2 - 9

Expanding the right side of the equation: (2x - 3)^2 - 18 = (2x - 3)(2x - 3) - 18 = (4x^2 - 6x - 6x + 9) - 18 = 4x^2 - 12x + 9 - 18 = 4x^2 - 12x - 9

Now we can equate the two sides of the equation: x^2 - 9 = 4x^2 - 12x - 9

Rearranging the equation: 0 = 3x^2 - 12x

Factoring out 3x: 0 = 3x(x - 4)

Setting each factor equal to zero: 3x = 0 -> x = 0 x - 4 = 0 -> x = 4

So the solutions to the equation are x = 0 and x = 4.