Question

Log3 0,9 + Log3 10.............

Answer 1

Log(3) 0,9 +log(3)10 = log(3) 9/10 +log(3)10 = log(3)9 - log(3)10+log(3)10 =
=log(3)9 = log(3) 3^2=2log(3)3=2

Answer 2

Log3 0.9+log3 10=log3 (0.9*10)=log3 9=2 

Answer 3

To simplify the expression, let's use the logarithmic identity:

logₐ(b) + logₐ(c) = logₐ(b * c)

Applying this identity to the given expression:

log₃(0.9) + log₃(10) = log₃(0.9 * 10)

Multiplying 0.9 and 10:

log₃(0.9 * 10) = log₃(9)

The logarithm of 9 to the base 3 is equal to 2. Therefore:

log₃(0.9) + log₃(10) = 2