Question

(x^2+x)^2-5 (x^2+x)+6=0

Answer 1

Х^4+х^3+х^2-5х^2-5х+6=0
х^4+х^3-4х^2-5х+6=0

Answer 2

To solve the quadratic equation (x^2 + x)^2 - 5(x^2 + x) + 6 = 0, we can simplify the equation and then factor it.

Let's simplify the equation step by step:

Start with the given equation: (x^2 + x)^2 - 5(x^2 + x) + 6 = 0

Expand the squared term: (x^4 + 2x^3 + x^2) - 5(x^2 + x) + 6 = 0

Distribute the -5: x^4 + 2x^3 + x^2 - 5x^2 - 5x + 6 = 0

Combine like terms: x^4 + 2x^3 - 4x^2 - 5x + 6 = 0

Now, we can try factoring the equation. However, this equation does not appear to be easily factorable. In such cases, we can use numerical methods or an algebraic calculator to find the solutions.