Question

1)3-2(u-1)>8+u; 2)5(u+2)+14<6-u;

Answer 1

Решение ниже на фото все легко,и просто
Вот и все!

Answer 2

Let's solve each inequality step by step:

1. 3 - 2(u - 1) > 8 + u

First, let's simplify the inequality:

3 - 2u + 2 > 8 + u

Combine like terms:

5 - 2u > 8 + u

Next, let's isolate the variable terms on one side:

-2u - u > 8 - 5

-3u > 3

To isolate u, we divide both sides of the inequality by -3. Since we divide by a negative number, we need to flip the inequality sign:

u < 3/-3 u < -1

Therefore, the solution for the inequality is u < -1.

2. 5(u + 2) + 14 < 6 - u

First, let's simplify the inequality:

5u + 10 + 14 < 6 - u

Combine like terms:

5u + 24 < 6 - u

Next, let's isolate the variable terms on one side:

5u + u < 6 - 24

6u < -18

To isolate u, we divide both sides of the inequality by 6:

u < -18/6 u < -3

Therefore, the solution for the inequality is u < -3.