Question

Sin(x-P/6)=корень2/2

Answer 1

Ответ:

Пошаговое объяснение:

sin \alpha =√2/2

\alpha = \pi /4+2 \pi n b 3 \pi /4

1) х- \pi /6= \pi /4+2 \pi n

   x= \pi /4+ \pi /6+2 \pi n

   x=5 \pi /12+2 \pi n n⊂Z

2) x- \pi /6=3 \pi /4+2 \pi k

  x=11 \pi /12+2  \pi k n⊂Z

Answer 2

To solve the equation sin(x - π/6) = √2/2, we can use some trigonometric identities.

First, let's rewrite √2/2 as sin(π/4), since sin(π/4) = √2/2.

The equation becomes: sin(x - π/6) = sin(π/4)

Now, we can use the identity sin(a) = sin(b) to find the solutions: x - π/6 = π/4 + 2πn (where n is an integer)

To solve for x, we can add π/6 to both sides: x = π/4 + π/6 + 2πn

Simplifying further: x = (3π + 2πn)/12

So, the general solution for x is: x = (3π + 2πn)/12, where n is an integer.