Question

1)3,6t+10=0,6t+10 2)1x+41,3=x+0,3 3)x(x-4)=0

Answer 1

1. 3,6t + 10 = 0,6t + 10
3,6t - 0,6t = 10 - 10
3t = 0
t = 0

2. x + 41,3 = x + 0,3
x - x = 0,3 - 41,3
0 ≠ -41

3. x(x - 4) = 0
x = 0, або(или)
х - 4 = 0
х = 4

Answer 2

Let's solve each equation step by step:

1. 3,6t + 10 = 0,6t + 10

First, let's simplify the equation by subtracting 10 from both sides:

3,6t = 0,6t

Next, let's isolate the variable t by subtracting 0,6t from both sides:

3,6t - 0,6t = 0

Simplifying further:

3t = 0

Finally, divide both sides by 3 to solve for t:

t = 0

Therefore, the solution to the equation is t = 0.

2. 1x + 41,3 = x + 0,3

First, let's simplify the equation by subtracting x from both sides:

1x - x + 41,3 = 0,3

Simplifying further:

41,3 = 0,3

This equation is inconsistent because there is no value of x that satisfies it. Therefore, there is no solution to the equation.

3. x(x - 4) = 0

This equation is a quadratic equation. To solve it, we need to set each factor equal to zero and solve for x:

Setting x = 0:

x = 0

Setting x - 4 = 0:

x - 4 = 0 x = 4

Therefore, the solutions to the equation are x = 0 and x = 4.