Question

20:(6 3\11+1 8\11)+ (7 2\5-5,8) :5

Answer 1

20÷(6 3/11+1 8/11)+(7 2/5-5,8)÷5=2,82
1)6 3/11+1 8/11=7 11/11=8
2)20÷8=2,5
3)7 2/5-5,8=7,4-5,8=1,6
4)1,6÷5=0,32
5)2,5+0,32=2,82

Answer 2

To solve the expression 20:(6 3/11 + 1 8/11) + (7 2/5 - 5 8/10) : 5, let's break it down step by step:

Step 1: Convert mixed numbers to improper fractions: 6 3/11 = (11 * 6 + 3) / 11 = 69/11 1 8/11 = (11 * 1 + 8) / 11 = 19/11 7 2/5 = (5 * 7 + 2) / 5 = 37/5 5 8/10 = (10 * 5 + 8) / 10 = 58/10 = 29/5

Step 2: Perform the operations inside the parentheses: (69/11 + 19/11) = 88/11 (37/5 - 29/5) = 8/5

Step 3: Perform the division and addition: 20 / (88/11 + 8/5) = 20 / (40/5 + 88/11) 20 / (40/5 + 80/10) = 20 / (40/5 + 40/5) 20 / (80/5) = 20 * (5/80) 20 * (1/16) = 20/16 = 5/4

Step 4: Perform the final division: (5/4) / 5 = (5/4) * (1/5) = 5/20 = 1/4

Therefore, the value of the expression 20:(6 3/11 + 1 8/11) + (7 2/5 - 5 8/10) : 5 is 1/4.