Question

У=-12ײ+3

Answer 1

Какой вопрос? Или надо график?

Answer 2

The equation you provided is a quadratic equation in the form of:

U = -12x² + 3

In this equation, U represents the dependent variable, and x represents the independent variable. The equation is a quadratic function because of the presence of the x² term.

The general form of a quadratic equation is U = ax² + bx + c, where a, b, and c are constants. In your equation, a = -12, b = 0, and c = 3.

The graph of a quadratic function is a parabola. The coefficient "a" determines whether the parabola opens upwards or downwards. In this case, since "a" is negative (-12), the parabola opens downwards.

The vertex of the parabola can be found using the formula x = -b / (2a), which gives the x-coordinate of the vertex. In this case, since b = 0, the x-coordinate of the vertex is x = 0.

To find the y-coordinate of the vertex, substitute the x-coordinate (0) back into the equation:

U = -12(0)² + 3 U = 0 + 3 U = 3

Therefore, the vertex of the parabola is at (0, 3). The parabola opens downwards, and its vertex is the highest point on the graph.

You can plot additional points to create a graph of the quadratic equation. For example, when x = 1:

U = -12(1)² + 3 U = -12 + 3 U = -9

So, when x = 1, U = -9. You can continue this process to find more points and sketch the graph of the quadratic equation.