Question

В треуголькике АВС АС=ВС. Уугол С=70°. Найдите внешний угол СВD.Ответ дайте в градусах.

Answer 1

Это же легко нужно 180°-70°=110°
Ответ:110°
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Answer 2

Problem Analysis

We are given a triangle ABC, where AC = BC and angle C = 70°. We need to find the external angle CBD.

Solution

To find the external angle CBD, we can use the fact that the sum of the measures of the angles of a triangle is 180°. Since angle C is 70°, we can find angle A using the equation:

angle A = 180° - angle C - angle B

Since AC = BC, angle A = angle B. Therefore, we can rewrite the equation as:

angle A = 180° - angle C - angle A

Simplifying the equation, we get:

2 * angle A = 180° - angle C

Now we can solve for angle A:

angle A = (180° - angle C) / 2

Substituting the given value of angle C (70°), we can calculate angle A:

angle A = (180° - 70°) / 2 = 55°

Since angle A = angle B = 55°, we can find the external angle CBD using the equation:

external angle CBD = angle A + angle B

Substituting the value of angle A (55°), we can calculate the external angle CBD:

external angle CBD = 55° + 55° = 110°

Therefore, the external angle CBD is 110°.

Answer

The external angle CBD in triangle ABC, where AC = BC and angle C = 70°, is 110°.