Question

в треугольнике ABC CH - высота, AD - биссектриса, О - точка пересечения прямых CH и BAD 12градусов. Нйдите угол AOC. Ответ дать в градусах

Answer 1

AOC=180-(180-90-12)=78градусов

 

Answer 2

Triangle ABC and Angle AOC

In triangle ABC, where CH is the height, AD is the bisector, and O is the intersection point of lines CH and BAD, we are given that angle BAD is 12 degrees. We need to find angle AOC.

To find angle AOC, we can use the fact that the sum of the angles in a triangle is always 180 degrees. We can start by finding angle BAC.

Since AD is the bisector of angle BAC, we know that angle BAD is equal to angle CAD. Therefore, angle BAC is equal to 2 times angle BAD, which is 2 times 12 degrees, or 24 degrees.

Now, let's find angle ABC. Since CH is the height of triangle ABC, angle ABC is a right angle (90 degrees).

To find angle ACB, we can subtract angles BAC and ABC from 180 degrees. Therefore, angle ACB is equal to 180 degrees minus 24 degrees minus 90 degrees, which is 66 degrees.

Finally, to find angle AOC, we can subtract angle ACB from 180 degrees. Therefore, angle AOC is equal to 180 degrees minus 66 degrees, which is 114 degrees.