Question

Найдите стороны равнобедреного треугольника, периметр которого равен 32 см, а основание на 5 см больше боковой стороны. ДАНО, НАЙТИ, РЕШЕНИЕ ПОЖАЛУЙСТА

Answer 1

Дано: АВС-треугольник  Р=З2см  АВ=ВС

Найти: АВ ВС СА

Решение: обозначим АВ за x ,тогда основание равно 5+x  т.к в равнобедренном треугольнике боковые стороны равны то ВС=x

5+x+x+x=32

5+3x=32

3x=27

x=9

АВ=9  ВС=9 СА=14

Answer 2

Finding the sides of an isosceles triangle

To find the sides of an isosceles triangle, we can use the given information that the perimeter is 32 cm and the base is 5 cm longer than the side. Let's denote the length of the side as x.

The perimeter of a triangle is the sum of all its sides. In this case, we have two equal sides and one base. So we can write the equation:

x + x + (x + 5) = 32

Simplifying the equation, we get:

2x + x + 5 = 32

Combining like terms, we have:

3x + 5 = 32

Subtracting 5 from both sides, we get:

3x = 27

Dividing both sides by 3, we find:

x = 9

Therefore, the length of each equal side of the triangle is 9 cm.

Verification:

Let's verify our solution by calculating the perimeter of the triangle using the side length we found.

The perimeter of a triangle is given by the formula:

Perimeter = side1 + side2 + base

In this case, side1 and side2 are both equal to 9 cm, and the base is 5 cm longer than the side. So we have:

Perimeter = 9 + 9 + (9 + 5) = 32 cm

Our solution is verified as the perimeter matches the given value.

Therefore, the sides of the isosceles triangle are 9 cm, 9 cm, and 14 cm (base).

Note: The solution is based on the information provided and the assumption that the triangle is isosceles.