Question

АВС треугольник АВ 10 ВН высота СН 3 АН 6 угол А.45 Найти площадь

Answer 1

AC=AH+CH =9
По теореме Пифагора:
ВН= √(10²-6²)=√64=8
S= 1/2×BH×AC=4×9=36
Ответ : 36

Answer 2

Finding the Area of Triangle ABC

To find the area of triangle ABC, we can use the formula:

Area = (1/2) * base * height

Given: - AB = 10 (base) - HN = 3 (height) - AH = 6

First, we need to find the length of BC, which is the side opposite to angle A.

Using the Pythagorean theorem, we can find BC: BC = √(AB^2 - AH^2) BC = √(10^2 - 6^2) BC = √(100 - 36) BC = √64 BC = 8

Now that we have the base (AB = 10) and the height (HN = 3), we can calculate the area of triangle ABC:

Area = (1/2) * AB * HN Area = (1/2) * 10 * 3 Area = 15 square units

So, the area of triangle ABC is 15 square units.

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