Question

Внутри треугольника ABC взята точка K так что угол ABK=30, KAB=10.Найти угол KAC, если ABC=80 и AC=BC

Answer 1

Поможет площадь.
SΔ = 1/2·72·72·Sin30 = 72·72=5184
SΔ = 1/2·BC·AH
5184 = 1/2·72·AH
AH = 5184:36=144 По-моему так если нет то скажи

Answer 2

Given Information:

- Triangle ABC - Point K inside triangle ABC - Angle ABK = 30 degrees - Angle KAB = 10 degrees - Angle ABC = 80 degrees - AC = BC

To Find:

Angle KAC

Approach:

To find angle KAC, we can use the fact that the angles in a triangle add up to 180 degrees.

Let's start by finding angle BAC: Since angle ABC = 80 degrees and angle ABK = 30 degrees, we can find angle BAK: BAK = ABC - ABK = 80 - 30 = 50 degrees.

Now, we can find angle BCA: Since AC = BC, triangle ABC is an isosceles triangle. In an isosceles triangle, the base angles are equal. Therefore, angle BCA = angle BAC = 50 degrees.

Finally, we can find angle KAC: Angle KAC = Angle BAC - Angle BAK = 50 - 10 = 40 degrees.

Answer:

Angle KAC is 40 degrees.