Question

Периметар равнобедренного треугольника ABC равен 13 см .найдите длины его сторон,если основание меньше боковой стараны на 2 см.

Answer 1

Основание -х
бок. сторона=2+х
13= х+2 (2+х)
13=3х+4
3х=9
х=3 -основание
бок. сторона= 2+3=5
Ответ: 3; 5; 5.

Answer 2

Perimeter of an Isosceles Triangle

To find the lengths of the sides of an isosceles triangle ABC, given that the perimeter is 13 cm and the base is 2 cm shorter than the other side, we can use the following steps:

1. Let's assume that the length of the base of the triangle is x cm. 2. Since the base is 2 cm shorter than the other side, the length of the other two sides will be (x + 2) cm. 3. The perimeter of the triangle is the sum of all three sides, which is given as 13 cm. 4. Using the information above, we can set up the equation: x + (x + 2) + (x + 2) = 13. 5. Simplifying the equation, we get: 3x + 4 = 13. 6. Solving for x, we subtract 4 from both sides: 3x = 9. 7. Dividing both sides by 3, we find: x = 3.

Therefore, the length of the base of the triangle is 3 cm, and the lengths of the other two sides are (3 + 2) = 5 cm.

Answer: The lengths of the sides of the isosceles triangle ABC are as follows: - Base (AB): 3 cm - Other two sides (AC and BC): 5 cm each.

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