Question

в прямоугольнике АВСD сторона ВС равна 18 см. растояние от точки пересечения диагоналей до этой стороны равно 7 см. чему равен Р прямоугольника?

Answer 1

АВ=CD=7х2=14см;         Р=(ВС+АВ)х2=(14+18)х2=32х2=64см. Ответ:64 см. равен периметр.

 

Answer 2

Calculation of the Perimeter of Rectangle ABCD

To find the perimeter of rectangle ABCD, we need to know the lengths of its sides. From the given information, we know that side BC is equal to 18 cm and the distance from the intersection of the diagonals to side BC is 7 cm.

Let's denote the length of side AB as x. Since the diagonals of a rectangle bisect each other, we can conclude that the distance from the intersection of the diagonals to side AB is also 7 cm. Therefore, we can write the following equation:

x + 7 + x + 7 = 18

Simplifying the equation, we get:

2x + 14 = 18

Subtracting 14 from both sides, we have:

2x = 4

Dividing both sides by 2, we find:

x = 2

So, the length of side AB is 2 cm. Since opposite sides of a rectangle are equal in length, we can conclude that side CD is also 2 cm.

Now, we can calculate the perimeter of rectangle ABCD by adding up the lengths of all four sides:

Perimeter (P) = AB + BC + CD + DA = 2 + 18 + 2 + 18 = 40 cm

Therefore, the perimeter of rectangle ABCD is 40 cm.