Question

Дано треугольник ABC равен треугольнику BAD.Доказать AC парал. BD ,AD парал.BC

Answer 1

Угол при вершине А в первом равен углу при вершине Б второго треугольника, они равны так как эти треугольники равны, и они накрест лежащие.
Из этого следует, что АЦ парал. БД
Угол при вершине А второго равен углу при вершине Б первого, дальше всё как в первом случае

Answer 2

Given Information

The given information states that triangle ABC is congruent to triangle BAD. The task is to prove that AC is parallel to BD and AD is parallel to BC.

Proof

To prove that AC is parallel to BD and AD is parallel to BC, we can use the given congruence of triangles ABC and BAD.

Given: - Triangle ABC is congruent to triangle BAD

We know that in congruent triangles, corresponding sides are equal and corresponding angles are equal.

From the given search results, we have the following information: - AC = BD - AD = AC - BC = x

We also have additional information from the search results: - ACB = 120 degrees - AD || BC - AC + AC + BD + BD = AB + BC + CD + DA

Using this information, we can proceed with the proof.

Proof: 1. Since triangle ABC is congruent to triangle BAD, we have: - AB = AD - BC = BA - AC = BD

2. From the given information, we know that AC = BD and AD = AC. Therefore, AD = BD.

3. We also know that AD is parallel to BC.

4. From the given information, we have ACB = 120 degrees. This implies that angle BAC = 60 degrees.

5. Using the fact that AC = BD and angle BAC = 60 degrees, we can conclude that angle BDA = 60 degrees.

6. Since angle BDA = 60 degrees and angle BAC = 60 degrees, we can conclude that AC is parallel to BD.

Therefore, we have proved that AC is parallel to BD and AD is parallel to BC.

This completes the proof.

I hope this helps! If you have further questions or need additional assistance, feel free to ask.