Question

В равнобедренном треугольнике ABC К основанию треугольника проведена высота АМ. Градусная мера угла B AC равна 48°.Найдите градусные меры углов MAC и CMAВыберите правильный ответ.24-и 9024 и 24°48 и 2448° и 90°- НазадВпеATBU Window​

Answer 1

Угол АСМ находится по свойству углов треугольника, а угол ВСМ по свойству равнобедренного треугольника

Answer 2

To find the degree measures of angles MAC and CMA in an isosceles triangle ABC with a base AC and a height AM, we can use the fact that the sum of the angles in a triangle is always 180 degrees.

Given that angle BAC is 48 degrees, we can determine the degree measures of angles MAC and CMA as follows:

Angle MAC:

Since triangle ABC is isosceles, we know that angle BCA is also 48 degrees. Angle MAC is formed by the height AM and the base AC. Therefore, angle MAC is equal to half of the difference between 180 degrees and the sum of angles BAC and BCA.

Let's calculate it: MAC = (180 - (BAC + BCA)) / 2 MAC = (180 - (48 + 48)) / 2 MAC = 84 / 2 MAC = 42 degrees

Angle CMA:

Since triangle ABC is isosceles, we know that angle BAC is equal to angle BCA, which is 48 degrees. Angle CMA is formed by the height AM and the side BC. Therefore, angle CMA is equal to half of the difference between 180 degrees and the sum of angles BAC and BCA.

Let's calculate it: CMA = (180 - (BAC + BCA)) / 2 CMA = (180 - (48 + 48)) / 2 CMA = 84 / 2 CMA = 42 degrees

Therefore, the degree measures of angles MAC and CMA in triangle ABC are both 42 degrees.

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