Question

В тупоугольном треугольнике АВС, АС=5 , ВС=3. Найдите высоту,опущенную на сторону АС,если высота,опущенная на сторону ВС равна 2. Решите пожалуйста , подробно

Answer 1

Решение в приложении.

Answer 2

Finding the Height of the Triangle

To find the height of the triangle, we can use the formula for the area of a triangle, which is given by the formula:

Area = (1/2) * base * height

In this case, the base of the triangle is AC and the height is the height of the triangle, h. The area of the triangle can also be calculated using the formula:

Area = (1/2) * base * height

We can use the given values of AC and BC to find the area of the triangle and then solve for the height.

Calculating the Area of the Triangle

The area of the triangle can be calculated using the formula:

Area = (1/2) * base * height

Given that AC = 5 and BC = 3, we can substitute these values into the formula to find the area of the triangle.

Area = (1/2) * 5 * h

Solving for the Height

We also know that the area of the triangle can be calculated using the given values of AC and BC. The area of the triangle is also given by the formula:

Area = (1/2) * base * height

Given that AC = 5, BC = 3, and the height on BC is 2, we can use this information to solve for the height of the triangle.

Area = (1/2) * 5 * 2

Now, we can solve for the height of the triangle.

Area = (1/2) * 5 * 2 = (1/2) * 10 = 5

So, the area of the triangle is 5.

Finding the Height

Now that we know the area of the triangle is 5, we can use this information to solve for the height of the triangle using the formula:

Area = (1/2) * base * height

Substituting the known values, we have:

5 = (1/2) * 5 * h

Solving for h:

5 = (1/2) * 5 * h

5 = 2.5h

h = 5 / 2.5

h = 2

Therefore, the height of the triangle, dropped from point A to side BC, is 2.