Question

составьте уравнения химической реакции,происходящей между высшим оксидом химического элемента с порядковым номером 14 в ПСХЭ Д И Менделеева и гидроксидом ,образованным химическим элементом с порядковым номером 19 Назовите полученные вещества Укажите тип реакции

Answer 1

Chemical Reaction between a Higher Oxide and Hydroxide

To determine the chemical reaction between a higher oxide of an element with atomic number 14 in Mendeleev's Periodic System of Chemical Elements (PSCE) and a hydroxide formed by an element with atomic number 19, we need to identify the elements involved.

The element with atomic number 14 in the PSCE is silicon (Si), and the element with atomic number 19 is potassium (K). Therefore, we are looking for the chemical reaction between a higher oxide of silicon and a hydroxide of potassium.

Unfortunately, the search results provided do not contain the specific information needed to determine the chemical reaction and the resulting substances. However, based on the given elements, we can make an educated guess about the possible reaction.

Possible Chemical Reaction: One possible chemical reaction could be the reaction between silicon dioxide (SiO2), which is a higher oxide of silicon, and potassium hydroxide (KOH), which is a hydroxide of potassium. The balanced chemical equation for this reaction would be:

SiO2 + 2KOH → K2SiO3 + H2O

In this reaction, silicon dioxide reacts with potassium hydroxide to form potassium silicate (K2SiO3) and water (H2O).

Type of Reaction: The reaction between silicon dioxide and potassium hydroxide is an acid-base reaction, specifically a neutralization reaction. Silicon dioxide acts as an acid, and potassium hydroxide acts as a base. The reaction between an acid and a base results in the formation of a salt (potassium silicate) and water.

Please note that the provided chemical reaction is an educated guess based on the given elements. If you have more specific information or context, I can provide a more accurate answer.