Question

Вычислите количество вещества, которое составляют 40 кг сульфата железа (III). Сколько ионов каждого вида будет содержать это количество?

Answer 1

Calculation of the Amount of Iron(III) Sulfate

To calculate the amount of substance (also known as the number of moles) in 40 kg of iron(III) sulfate, we need to use the formula:

Amount of substance (in moles) = Mass / Molar mass

The molar mass of iron(III) sulfate (Fe2(SO4)3) can be calculated by summing the atomic masses of its constituent elements:

- Atomic mass of iron (Fe) = 55.845 g/mol - Atomic mass of sulfur (S) = 32.06 g/mol - Atomic mass of oxygen (O) = 16.00 g/mol

The molar mass of iron(III) sulfate is therefore:

Molar mass of Fe2(SO4)3 = (2 * Atomic mass of Fe) + (3 * Atomic mass of S) + (12 * Atomic mass of O)

Let's calculate the molar mass:

Molar mass of Fe2(SO4)3 = (2 * 55.845 g/mol) + (3 * 32.06 g/mol) + (12 * 16.00 g/mol)

Using the given atomic masses, we can calculate the molar mass of iron(III) sulfate.