Question

Поставьте коэффициенты в уравнении 1 )KMnO4+H2SO4=K2SO4+MnSO4 +O3+H2O :2)NaI + H2SO4=Na2SO4+H2S+I2+H2O: 3)Cu +HNO3=Cu(NO3)2+NO+H20

Answer 1

1) 6KMnO4 + 9H2SO4 = 3K2SO4 + 6MnSO4 + 5O3 + 9H2O 
2) 8NaI + 5H2SO4 = 4Na2SO4 + H2S + 4I2 + 4H2O
3) 3Cu0 + 8HN+5O3 → 3Cu+2(NO3) 2 + 2N+2O + 4H2O

Answer 2

Equation 1: KMnO4 + H2SO4 = K2SO4 + MnSO4 + O3 + H2O

The balanced equation for the reaction between potassium permanganate (KMnO4) and sulfuric acid (H2SO4) is:

2 KMnO4 + 3 H2SO4 = K2SO4 + 2 MnSO4 + 3 O3 + 3 H2O

This equation shows that 2 moles of KMnO4 react with 3 moles of H2SO4 to produce 1 mole of K2SO4, 2 moles of MnSO4, 3 moles of O3 (ozone), and 3 moles of H2O (water).

Equation 2: NaI + H2SO4 = Na2SO4 + H2S + I2 + H2O

The balanced equation for the reaction between sodium iodide (NaI) and sulfuric acid (H2SO4) is:

2 NaI + H2SO4 = Na2SO4 + H2S + I2 + 2 H2O

This equation shows that 2 moles of NaI react with 1 mole of H2SO4 to produce 1 mole of Na2SO4, 1 mole of H2S, 1 mole of I2, and 2 moles of H2O.

Equation 3: Cu + HNO3 = Cu(NO3)2 + NO + H2O

The balanced equation for the reaction between copper (Cu) and nitric acid (HNO3) is:

3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

This equation shows that 3 moles of Cu react with 8 moles of HNO3 to produce 3 moles of Cu(NO3)2, 2 moles of NO, and 4 moles of H2O.

Please note that the coefficients in balanced chemical equations represent the ratio of moles of each substance involved in the reaction. These coefficients ensure that the law of conservation of mass is satisfied, meaning that the total mass of the reactants is equal to the total mass of the products.

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