Question

№7. Рассчитайте массовые доли элементов в тротиле: C7H5N3O6

Answer 1

Смотри фото если что-то не понятно пиши в коменты

Answer 2

Calculation of Mass Fractions in TNT (C7H5N3O6)

To calculate the mass fractions of elements in TNT (trinitrotoluene), we need to determine the molar mass of each element in the compound and then calculate the mass fraction based on their respective molar masses.

The molecular formula of TNT is C7H5N3O6. Let's calculate the molar mass of each element:

- Carbon (C): Atomic mass = 12.01 g/mol - Hydrogen (H): Atomic mass = 1.01 g/mol - Nitrogen (N): Atomic mass = 14.01 g/mol - Oxygen (O): Atomic mass = 16.00 g/mol

Now, let's calculate the molar mass of TNT:

Molar mass of TNT (C7H5N3O6) = (7 * molar mass of C) + (5 * molar mass of H) + (3 * molar mass of N) + (6 * molar mass of O)

Molar mass of TNT = (7 * 12.01 g/mol) + (5 * 1.01 g/mol) + (3 * 14.01 g/mol) + (6 * 16.00 g/mol)

Molar mass of TNT = 227.13 g/mol

To calculate the mass fraction of each element, we divide the molar mass of each element by the molar mass of TNT and multiply by 100%.

Mass fraction of Carbon (C) = (7 * 12.01 g/mol) / 227.13 g/mol * 100% Mass fraction of Hydrogen (H) = (5 * 1.01 g/mol) / 227.13 g/mol * 100% Mass fraction of Nitrogen (N) = (3 * 14.01 g/mol) / 227.13 g/mol * 100% Mass fraction of Oxygen (O) = (6 * 16.00 g/mol) / 227.13 g/mol * 100%

Let's calculate the mass fractions:

Mass fraction of Carbon (C) = (7 * 12.01 g/mol) / 227.13 g/mol * 100% = 37.06% Mass fraction of Hydrogen (H) = (5 * 1.01 g/mol) / 227.13 g/mol * 100% = 2.24% Mass fraction of Nitrogen (N) = (3 * 14.01 g/mol) / 227.13 g/mol * 100% = 29.25% Mass fraction of Oxygen (O) = (6 * 16.00 g/mol) / 227.13 g/mol * 100% = 31.45%

Therefore, the mass fractions of elements in TNT (C7H5N3O6) are approximately:

- Carbon (C): 37.06% - Hydrogen (H): 2.24% - Nitrogen (N): 29.25% - Oxygen (O): 31.45%

Please note that these values are approximate and may vary slightly depending on the specific isotopic composition of the elements.