Question

Для B,C,N,O,F,Ne,Na написать распределение электронов.

Answer 1

B - 2s^2p^1 так что ли?

C - 2s^2p^2 и так далее по порядку

B,C,N,O,F,Ne,

Na - [Ne]3s^1

Answer 2

B-1s2, 2s2, 2p 1

C-1s2, 2s2, 2p2

N-1s2, 2s2, 2p 3

O 1s2, 2s2, 2p 4

F-1s2, 2s2, 2p 5

Ne-1s2, 2s2, 2p 6

Na не могу составить! Только так

Answer 3

Electron Distribution for B, C, N, O, F, Ne, Na

The electron distribution for the elements B (Boron), C (Carbon), N (Nitrogen), O (Oxygen), F (Fluorine), Ne (Neon), and Na (Sodium) can be determined by looking at their respective electron configurations. The electron configuration describes the arrangement of electrons in an atom's energy levels or shells.

Here is the electron distribution for each of these elements:

1. Boron (B): The atomic number of boron is 5. The electron configuration of boron is 1s^2 2s^2 2p^1. This means that boron has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 1 electron in the 2p orbital.

2. Carbon (C): The atomic number of carbon is 6. The electron configuration of carbon is 1s^2 2s^2 2p^2. This means that carbon has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 2 electrons in the 2p orbital.

3. Nitrogen (N): The atomic number of nitrogen is 7. The electron configuration of nitrogen is 1s^2 2s^2 2p^3. This means that nitrogen has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 3 electrons in the 2p orbital.

4. Oxygen (O): The atomic number of oxygen is 8. The electron configuration of oxygen is 1s^2 2s^2 2p^4. This means that oxygen has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 4 electrons in the 2p orbital.

5. Fluorine (F): The atomic number of fluorine is 9. The electron configuration of fluorine is 1s^2 2s^2 2p^5. This means that fluorine has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 5 electrons in the 2p orbital.

6. Neon (Ne): The atomic number of neon is 10. The electron configuration of neon is 1s^2 2s^2 2p^6. This means that neon has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 6 electrons in the 2p orbital.

7. Sodium (Na): The atomic number of sodium is 11. The electron configuration of sodium is 1s^2 2s^2 2p^6 3s^1. This means that sodium has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, 6 electrons in the 2p orbital, and 1 electron in the 3s orbital.

Please note that the electron distribution provided above is based on the electron configuration of each element.