Question

Составьте термохимическое уравнение реакции горения натрия в хлоре, если известно, что при сгорании 1,8*10^23 его атомов выделилось количество теплоты, равное 1233 кДж. Помогите если нетрудно! Буду благодарен!

Answer 1

2Na+Cl2=2NaCl Кол.в-ва натрия равно 1,8*10^23/6,02*10^23моль⁻¹ = 0,3моль => для 1 моль атомов Na количество теплоты равно 1233кДж*1моль/0,3моль=4110кДж

Answer 2

Thermodynamic Equation for the Combustion of Sodium in Chlorine

The combustion of sodium in chlorine can be represented by the following balanced chemical equation:

2 Na(s) + Cl2(g) -> 2 NaCl(s)

To determine the thermodynamic equation for this reaction, we need to consider the enthalpy change (ΔH) associated with the combustion of 1 mole of sodium atoms.

Given that the combustion of 1.8 * 10^23 sodium atoms releases 1233 kJ of heat, we can calculate the enthalpy change per mole of sodium atoms.

To do this, we need to convert the given heat release from kJ to J and divide it by the Avogadro's number (6.022 * 10^23) to obtain the heat release per mole of sodium atoms.

Let's calculate the enthalpy change per mole of sodium atoms:

1233 kJ * 1000 J/kJ / (1.8 * 10^23) = 6.85 J

Therefore, the enthalpy change per mole of sodium atoms is 6.85 J.

Now, we can write the thermodynamic equation for the combustion of sodium in chlorine, including the enthalpy change:

2 Na(s) + Cl2(g) -> 2 NaCl(s) ΔH = -6.85 J/mol

Note that the negative sign indicates that the reaction is exothermic, meaning it releases heat.

Please let me know if there is anything else I can help you with!