Question

Помогите пожалуйста, с решением. :В Определите простейшую химическую формулу кислородосодержащего органического вещества по данным анализа: массовая доля углерода - 54.55%, водорода 9.09%. Что это за вещество?

Answer 1

Пусть масса вещества - 100г, тогда 

m(C) = w x 100/100% = 54,55% х 100/100% = 54,55г

m(Н) = w x 100/100% = 9,09% х 100/100% = 9,09г

m(O) = 100 = 54,55 - 9,09 = 36,36г

Находим сотношение атомов по формуле:

n = m/Ar

n(C) : n(H) : n(O) = 54,55/12 : 9,09/1 : 36,36/16 = 4,5 : 9 : 2,3 = 2 : 4 : 1

Формула - С2Н4О этаналь (уксусный альдегид)

Структурная:

              O    

             // 

CH3 - C 

             \

             H

 

Answer 2

У меня получился  уксусный альдегид С2Н4О 

Answer 3

Determining the Simplest Chemical Formula of an Oxygen-Containing Organic Substance

To determine the simplest chemical formula of an oxygen-containing organic substance based on the given analysis data, we need to calculate the mass percentage of oxygen in the substance. Unfortunately, the mass percentage of oxygen is not provided in the question. However, we can still proceed with the available information.

Let's assume that the mass percentage of oxygen is 36.36% (100% - 54.55% - 9.09%). This assumption is made to demonstrate the calculation process, but please note that the actual substance may have a different oxygen content.

To calculate the empirical formula, we need to convert the mass percentages into mole ratios. We can assume a 100g sample of the substance to simplify the calculations.

Given: - Mass percentage of carbon (C) = 54.55% - Mass percentage of hydrogen (H) = 9.09% - Mass percentage of oxygen (O) = 36.36% (assumed)

Step 1: Convert mass percentages to moles. - Moles of carbon (C) = (54.55g C) / (12.01 g/mol) = 4.54 mol C - Moles of hydrogen (H) = (9.09g H) / (1.01 g/mol) = 9.00 mol H - Moles of oxygen (O) = (36.36g O) / (16.00 g/mol) = 2.27 mol O (assumed)

Step 2: Divide the number of moles by the smallest number of moles to obtain the mole ratio. - Mole ratio of C : H : O = 4.54 : 9.00 : 2.27 (assumed)

Step 3: Simplify the mole ratio to the simplest whole-number ratio. - Divide all the mole ratios by the smallest number of moles (2.27) to obtain the simplest whole-number ratio. - Rounded to the nearest whole number, the simplest whole-number ratio is approximately 2 : 4 : 1.

Step 4: Write the empirical formula using the simplest whole-number ratio. - The empirical formula of the oxygen-containing organic substance, based on the given analysis data, is C2H4O.

Please note that this calculation assumes the mass percentage of oxygen to be 36.36%. If the actual mass percentage of oxygen is different, the empirical formula will also be different.