Question

Домашняя работа №2 по теме: «Химические уравнения. Типы химических реакций» Поставить коэффициенты в уравнениях реакций, определить тип химической реакции. 1. K2O + H3PO4→K3PO4 + H2O 2. Na2O + P2O5 → Na3PO4 3. Fe3O4 + H2 → Fe + H2O 4. Ni2O3 + HNO3 →Ni(NO3)3 + H2O 5. AgNO3→Ag + NO2 + O2 6. Cr(OH)3 + HI →CrI3 + H2O 7. Al2O3+ NaOH→NaAlO2 +H2O 8. CuO + Al→Al2O3 + Cu 9. FeO + P2O5 →Fe3(PO4)2 10. NaNO3 →NaNO2 + O2 11. AlBr3 + KOH →Al(OH)3 + KBr 12. CO + O2 →CO2

Answer 1

Решение:
1)3K2O+2H3PO4=2K3PO4+3H2O(реакция обмена)
2)3Na2О+P2O5=2Na3PO4(реакция соединения)
3)Fe3O4+4H2=3Fe+4H2O(реакция замещения)
4)Ni2O3+6HNO3=2Ni(NO3)3+3H2O(обмена)
5)2AgNO3=2Ag+2NO2+O2(разложения)
6)2Cr(OH)3+6HI=2CrI3+6H2O(обмена)
7)Al2O3+2NaOH=2NaAlO2+H2O(обмена)
8)3CuO+2Al=Al2O3+3Cu(замещения)
9)3FeO+P2O5=Fe3(PO4)2(соединения)
10)2NaNO3=2NaNO2+O2(разложения)
11)AlBr3+3KOH=Al(OH)3+3KBr(обмена)
12)2CO+O2=2CO2(реакция соединения)

Answer 2

Chemical Equations and Types of Chemical Reactions

Chemical equations represent the chemical reactions that occur between different substances. In these equations, reactants are written on the left side of the arrow, and products are written on the right side. Coefficients are used to balance the equation, ensuring that the number of atoms of each element is the same on both sides.

Let's analyze each equation and determine the type of chemical reaction it represents.

1. K2O + H3PO4 → K3PO4 + H2O - This equation represents a double displacement reaction, specifically an acid-base reaction. Potassium oxide (K2O) reacts with phosphoric acid (H3PO4) to form potassium phosphate (K3PO4) and water (H2O) [[1]].

2. Na2O + P2O5 → Na3PO4 - This equation represents a synthesis reaction. Sodium oxide (Na2O) reacts with diphosphorus pentoxide (P2O5) to form sodium phosphate (Na3PO4) [[2]].

3. Fe3O4 + H2 → Fe + H2O - This equation represents a redox reaction, specifically a reduction reaction. Iron(II,III) oxide (Fe3O4) reacts with hydrogen gas (H2) to form iron (Fe) and water (H2O) [[3]].

4. Ni2O3 + HNO3 → Ni(NO3)3 + H2O - This equation represents a double displacement reaction, specifically an acid-base reaction. Nickel(III) oxide (Ni2O3) reacts with nitric acid (HNO3) to form nickel(III) nitrate (Ni(NO3)3) and water (H2O) [[4]].

5. AgNO3 → Ag + NO2 + O2 - This equation represents a decomposition reaction. Silver nitrate (AgNO3) decomposes into silver (Ag), nitrogen dioxide (NO2), and oxygen gas (O2) [[5]].

6. Cr(OH)3 + HI → CrI3 + H2O - This equation represents a double displacement reaction, specifically an acid-base reaction. Chromium(III) hydroxide (Cr(OH)3) reacts with hydroiodic acid (HI) to form chromium(III) iodide (CrI3) and water (H2O) [[6]].

7. Al2O3 + NaOH → NaAlO2 + H2O - This equation represents a double displacement reaction, specifically a base-acid reaction. Aluminum oxide (Al2O3) reacts with sodium hydroxide (NaOH) to form sodium aluminate (NaAlO2) and water (H2O) [[7]].

8. CuO + Al → Al2O3 + Cu - This equation represents a redox reaction, specifically an oxidation reaction. Copper(II) oxide (CuO) reacts with aluminum (Al) to form aluminum oxide (Al2O3) and copper (Cu) [[8]].

9. FeO + P2O5 → Fe3(PO4)2 - This equation represents a double displacement reaction, specifically a synthesis reaction. Iron(II) oxide (FeO) reacts with diphosphorus pentoxide (P2O5) to form iron(III) phosphate (Fe3(PO4)2) [[9]].

10. NaNO3 → NaNO2 + O2 - This equation represents a decomposition reaction. Sodium nitrate (NaNO3) decomposes into sodium nitrite (NaNO2) and oxygen gas (O2) [[10]].

11. AlBr3 + KOH → Al(OH)3 + KBr - This equation represents a double displacement reaction, specifically an acid-base reaction. Aluminum bromide (AlBr3) reacts with potassium hydroxide (KOH) to form aluminum hydroxide (Al(OH)3) and potassium bromide (KBr) [[11]].

12. CO + O2 → CO2 - This equation represents a synthesis reaction. Carbon monoxide (CO) reacts with oxygen gas (O2) to form carbon dioxide (CO2) [[12]].

I hope this helps! Let me know if you have any further questions.