Question

Молекулярна форма AlCl3+NaOH=

Answer 1

AlCl3+3NaOH=3NaCl+Al(OH)3↓
Al(+3)+3OH(-)=Al(OH)3↓

Answer 2

AlCl₃+3NaOH=3NaCl+Al(OH)₃↓

Answer 3

Molecular equation for the reaction between AlCl3 and NaOH is:

AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl

In this reaction, AlCl3 (aluminum chloride) reacts with NaOH (sodium hydroxide) to form Al(OH)3 (aluminum hydroxide) and NaCl (sodium chloride).

The molecular formula of aluminum chloride is AlCl3, which means it consists of one aluminum atom bonded with three chloride atoms. The molecular formula of sodium hydroxide is NaOH, indicating it is composed of one sodium atom bonded with one oxygen atom and one hydrogen atom.

When these two compounds react, the aluminum chloride dissociates into its ions, releasing one aluminum ion (Al3+) and three chloride ions (Cl-) into the solution. Similarly, sodium hydroxide also dissociates into its ions, forming one sodium ion (Na+) and one hydroxide ion (OH-) in the solution.

The aluminum ion (Al3+) reacts with the hydroxide ion (OH-) to form aluminum hydroxide (Al(OH)3) precipitate. The sodium ion (Na+) from sodium hydroxide forms an ionic bond with the chloride ions (Cl-) from aluminum chloride, resulting in the formation of sodium chloride (NaCl) as a soluble compound.

The molecular shape of Al(OH)3 is a trigonal planar with a tetrahedral electron geometry around the aluminum atom. The hydroxide ions are arranged in a trigonal planar shape around the aluminum ion.

Overall, the reaction between AlCl3 and NaOH results in the formation of aluminum hydroxide precipitate and sodium chloride as the soluble compound.