Question

Раствор с массовой долей AgNO3 0,82 является насыщенным при 60 градусах. При охлаждении этого раствора массой 140 г до 10 градусов в осадок выпала соль массой 71,2 г. Определите коэффициент растворимости AgNO3 при 10 градусах.

Answer 1

Ну вот...
 (AgNO3) = 140*0.82 = 114.8 г
m (H2O) = 140 - 114.8 = 25.2 г
m (AgNO3) ₁₀° = 114.8 - 71.2 = 43.6 г
43,6 г AgNO3 - в 25.2 г Н2О
х г AgNO3 - в 100 г Н2О
х = 43,6*100/25,2= 173,02
s = 173.02 

Answer 2

Calculation of Solubility Coefficient of AgNO3 at 10 degrees Celsius

To determine the solubility coefficient of AgNO3 at 10 degrees Celsius, we can use the given information about the saturated solution at 60 degrees Celsius and the precipitate formed upon cooling.

Given: - Mass fraction of AgNO3 in the saturated solution at 60 degrees Celsius: 0.82 - Mass of the solution: 140 g - Mass of the precipitated salt: 71.2 g - Final temperature: 10 degrees Celsius

To find the solubility coefficient, we need to calculate the mass of AgNO3 that remains dissolved in the solution at 10 degrees Celsius.

Calculation Steps:

1. Calculate the mass of AgNO3 in the saturated solution at 60 degrees Celsius: - Mass of AgNO3 = Mass of the solution * Mass fraction of AgNO3 - Mass of AgNO3 = 140 g * 0.82 = 114.8 g

2. Calculate the mass of AgNO3 that precipitated upon cooling to 10 degrees Celsius: - Mass of AgNO3 precipitate = Mass of the solution at 60 degrees Celsius - Mass of the solution at 10 degrees Celsius - Mass of AgNO3 precipitate = 114.8 g - 71.2 g = 43.6 g

3. Calculate the solubility coefficient of AgNO3 at 10 degrees Celsius: - Solubility coefficient = Mass of AgNO3 precipitate / Mass of the solution at 10 degrees Celsius - Solubility coefficient = 43.6 g / 140 g = 0.3114

Therefore, the solubility coefficient of AgNO3 at 10 degrees Celsius is approximately 0.3114.

Please note that the calculation assumes ideal conditions and does not take into account any other factors that may affect the solubility of AgNO3 at different temperatures.