Question

Какая масса меди выделится при восстановлении из оксида меди(2),если для этого израсходовано 11,2л водорода(н.у.) Помогите пожалуйста)

Answer 1

CuO+H2 = Cu + H20
n.водорода.=11.2/22.1=0,5моль
m.меди.=  64*0,5=32гр.

Answer 2

Calculation of the Mass of Copper Formed

To calculate the mass of copper formed when copper(II) oxide is reduced using hydrogen gas, we need to use the balanced chemical equation for the reaction. The balanced equation is as follows:

CuO + H2 → Cu + H2O

From the equation, we can see that 1 mole of copper(II) oxide (CuO) reacts with 1 mole of hydrogen gas (H2) to produce 1 mole of copper (Cu) and 1 mole of water (H2O).

To determine the mass of copper formed, we need to know the molar mass of copper. The molar mass of copper is approximately 63.55 grams per mole.

Now, let's calculate the mass of copper formed using the given information that 11.2 liters of hydrogen gas (at standard temperature and pressure) is consumed in the reaction.

Calculation Steps:

Step 1: Convert the volume of hydrogen gas to moles using the ideal gas law.

The ideal gas law equation is given by:

PV = nRT

Where: P = pressure (in atm) V = volume (in liters) n = number of moles R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (in Kelvin)

Since the temperature and pressure are not given, we will assume standard temperature and pressure (STP), which is 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere (1 atm), respectively.

Using the ideal gas law, we can calculate the number of moles of hydrogen gas:

n = PV / RT

Substituting the given values: P = 1 atm V = 11.2 L R = 0.0821 L·atm/(mol·K) T = 273.15 K

We can now calculate the number of moles of hydrogen gas.

Step 2: Use the stoichiometry of the balanced equation to determine the number of moles of copper formed.

From the balanced equation, we know that 1 mole of copper(II) oxide reacts with 1 mole of hydrogen gas to produce 1 mole of copper. Therefore, the number of moles of copper formed will be the same as the number of moles of hydrogen gas consumed.

Step 3: Convert the number of moles of copper to grams using the molar mass of copper.

The molar mass of copper is approximately 63.55 grams per mole. Multiply the number of moles of copper by the molar mass to obtain the mass of copper formed.

Now, let's perform the calculations.

Calculation:

Step 1: Convert the volume of hydrogen gas to moles.

Using the ideal gas law: n = PV / RT n = (1 atm) * (11.2 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Calculating the value of n, we find: n ≈ 0.487 moles

Step 2: The number of moles of copper formed is equal to the number of moles of hydrogen gas consumed.

Therefore, the number of moles of copper formed is approximately 0.487 moles.

Step 3: Convert the number of moles of copper to grams using the molar mass of copper.

Mass of copper formed = (Number of moles of copper) * (Molar mass of copper) Mass of copper formed ≈ 0.487 moles * 63.55 g/mol

Calculating the value of the mass of copper formed, we find: Mass of copper formed ≈ 30.97 grams

Therefore, approximately 30.97 grams of copper will be formed when 11.2 liters of hydrogen gas (at standard temperature and pressure) is consumed in the reduction of copper(II) oxide.

Please note that the calculated value is an approximation and may vary depending on the conditions and purity of the reactants used.