Question

Дописать уравнения реакций,одно из них составить в ионном виде:1)KOH+CO22)KOH+H3PO43)KOH+CuCl24)Al(OH)3 в карточке дано одно вещество,спасибо за помощь

Answer 1

1)KOH+CO2=KHCO3

2)H3PO4 + 3KOH → 3H2O + K3PO4

3)2KOH + CuCl2 → 2KCl + Cu(OH)2↓
4)Al(OH)3=K[Al(OH)4]

Answer 2

2KOH+CO2 =K2CO3 + H2O.

3КОН+Н3РО4->К3РО4+3Н2О

СuСl2+2КОН->Сu(ОН)2 осадок+2КСl

 

Answer 3

Chemical Equations and Ionic Formulas

1) KOH + CO2: - Balanced equation: KOH + CO2 → K2CO3 + H2O - Ionic equation: 2KOH + CO2 → K2CO3 + H2O - Explanation: In this reaction, potassium hydroxide (KOH) reacts with carbon dioxide (CO2) to form potassium carbonate (K2CO3) and water (H2O) [[1]].

2) KOH + H3PO4: - Balanced equation: 3KOH + H3PO4 → K3PO4 + 3H2O - Ionic equation: 3KOH + H3PO4 → K3PO4 + 3H2O - Explanation: In this reaction, potassium hydroxide (KOH) reacts with phosphoric acid (H3PO4) to form potassium phosphate (K3PO4) and water (H2O) [[2]].

3) KOH + CuCl2: - Balanced equation: 2KOH + CuCl2 → Cu(OH)2 + 2KCl - Ionic equation: 2KOH + CuCl2 → Cu(OH)2 + 2KCl - Explanation: In this reaction, potassium hydroxide (KOH) reacts with copper(II) chloride (CuCl2) to form copper(II) hydroxide (Cu(OH)2) and potassium chloride (KCl) [[3]].

4) Al(OH)3: - Explanation: Aluminum hydroxide (Al(OH)3) is already in its ionic form. It consists of aluminum cations (Al3+) and hydroxide anions (OH-) [[4]].

I hope this helps! Let me know if you have any further questions.