Question

Дайте полный развернутый ответ с уравнениями реакций и расчетами!составьте уравнения реакций, соответствующих схеме превращения: 1 2 3СuO⇒CuSO4⇒CuCl2⇒Cu(OH)2Для реакции №3 составьте ионно-молекулярное уравнение реакции

Answer 1

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Answer 2

Scheme of Transformations:

1. CuO (Copper(II) oxide) → CuSO4 (Copper(II) sulfate) 2. CuSO4 (Copper(II) sulfate) → CuCl2 (Copper(II) chloride) 3. CuCl2 (Copper(II) chloride) → Cu(OH)2 (Copper(II) hydroxide)

Balanced Equations:

1. CuO + H2SO4 → CuSO4 + H2O 2. CuSO4 + 2HCl → CuCl2 + H2SO4 3. CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl

Ion-Molecular Equation for Reaction #3:

CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl

Explanation: 1. The first reaction involves the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) to form copper(II) sulfate (CuSO4) and water (H2O). The balanced equation for this reaction is:

CuO + H2SO4 → CuSO4 + H2O

2. The second reaction involves the reaction between copper(II) sulfate (CuSO4) and hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and sulfuric acid (H2SO4). The balanced equation for this reaction is:

CuSO4 + 2HCl → CuCl2 + H2SO4

3. The third reaction involves the reaction between copper(II) chloride (CuCl2) and sodium hydroxide (NaOH) to form copper(II) hydroxide (Cu(OH)2) and sodium chloride (NaCl). The balanced equation for this reaction is:

CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl

This is the ion-molecular equation for reaction #3. It represents the reactants and products in terms of their ions and molecules.

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