Question

Сколько кислорода (в молях) содержится в заправленном кислородном баллоне, если его емкость составляет 40 л, давление в нем 150 атм и температура газа 20 оС? Какое количество воздуха (м3) оказалось переработанным в кислород (содержание O2 в воздухе примите 21 объемн. %)? Помогите пожалуйста. С ответами не сходится вторая часть задачи((( Должно получиться 26.56 м3.

Answer 1

1) pV=nRT

  40*150=n*0.082*293

        n= 249.73

 

2) V(воздуха)=V(O2)/q(O2)=22.4*249.73/0.21=26637.87=26.64  м3.

 

Answer 2

Calculation of the Amount of Oxygen in the Oxygen Cylinder

To calculate the amount of oxygen in the oxygen cylinder, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Given: - Volume of the oxygen cylinder (V) = 40 L - Pressure in the cylinder (P) = 150 atm - Temperature of the gas (T) = 20 °C = 293.15 K

We need to convert the temperature from Celsius to Kelvin by adding 273.15.

Using the ideal gas law equation, we can solve for the number of moles (n) of oxygen in the cylinder:

n = PV / RT

Let's calculate it step by step:

1. Convert the pressure from atm to Pa (1 atm = 101325 Pa): Pressure (P) = 150 atm * 101325 Pa/atm = 15198750 Pa

2. Convert the volume from liters to cubic meters (1 L = 0.001 m^3): Volume (V) = 40 L * 0.001 m^3/L = 0.04 m^3

3. Convert the temperature from Celsius to Kelvin: Temperature (T) = 20 °C + 273.15 = 293.15 K

4. Calculate the number of moles (n) using the ideal gas law equation: n = (Pressure * Volume) / (R * Temperature)

The ideal gas constant (R) is 8.314 J/(mol·K).

Now, let's calculate the number of moles of oxygen in the cylinder:

n = (15198750 Pa * 0.04 m^3) / (8.314 J/(mol·K) * 293.15 K)

n ≈ 204.67 mol

Therefore, the amount of oxygen in the oxygen cylinder is approximately 204.67 moles.