Question

Написать полное сокращенное ионное уравнение CuSO4+NaOH

Answer 1

CuSO4+NaOH--> 2NaSO4+Cu(OH)2

Answer 2

Full Ionic Equation for CuSO4 + NaOH

The full ionic equation for the reaction between CuSO4 (copper(II) sulfate) and NaOH (sodium hydroxide) can be written as follows:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

This equation shows the complete dissociation of the reactants and products into their respective ions. The copper(II) sulfate dissociates into copper(II) ions (Cu2+) and sulfate ions (SO4^2-), while sodium hydroxide dissociates into sodium ions (Na+) and hydroxide ions (OH-). The reaction results in the formation of copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4).

Please note that this equation represents the balanced equation for the reaction, where the stoichiometric coefficients are not included in the ionic equation.