Question

Закончить уравнение реакции,и уравнять его 1) ?+H3PO4=?+H2 2) K20+?=KCl+? 3) ?+?=CuSO4+H2O 4)?+H2CO3=?+H2

Answer 1

1) 3Mg+2H3PO4=Mg3(PO4)2↓+3H2↑

2) K2O+2HCl=2KCl+H2O

3) CuO+H2SO4=CuSO4+H2O

4)Ca+H2CO3=CaCO3↓+H2↑

Answer 2

1) H3PO4 = H2O + H2 To balance this equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

Let's start by balancing the hydrogen (H) atoms. On the left side, we have 3 hydrogen atoms in H3PO4, and on the right side, we have 2 hydrogen atoms in H2O. To balance the hydrogen atoms, we can place a coefficient of 3 in front of H2O:

H3PO4 = 3H2O + H2

Next, let's balance the oxygen (O) atoms. On the left side, we have 4 oxygen atoms in H3PO4, and on the right side, we have 6 oxygen atoms in 3H2O. To balance the oxygen atoms, we can place a coefficient of 2 in front of H3PO4:

2H3PO4 = 3H2O + H2

Now, let's verify if the equation is balanced:

On the left side: 2 * 3 + 4 = 10 hydrogen and oxygen atoms On the right side: 3 * 2 + 1 = 7 hydrogen and oxygen atoms

The equation is not balanced yet. We need to balance the hydrogen and oxygen atoms simultaneously. To do this, we can place a coefficient of 4 in front of H2:

2H3PO4 = 3H2O + 4H2

Now, let's verify if the equation is balanced:

On the left side: 2 * 3 + 4 = 10 hydrogen and oxygen atoms On the right side: 3 * 2 + 4 = 10 hydrogen and oxygen atoms

The equation is now balanced.

2) K2O = 2KCl To balance this equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

Let's start by balancing the potassium (K) atoms. On the left side, we have 2 potassium atoms in K2O, and on the right side, we have 2 potassium atoms in 2KCl. The potassium atoms are already balanced.

Next, let's balance the chlorine (Cl) atoms. On the left side, we have 0 chlorine atoms in K2O, and on the right side, we have 2 chlorine atoms in 2KCl. To balance the chlorine atoms, we can place a coefficient of 2 in front of KCl:

K2O = 2KCl

The equation is now balanced.

3) ? + ? = CuSO4 + H2O To balance this equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

Let's start by balancing the hydrogen (H) atoms. On the left side, we have 2 hydrogen atoms in H2O, and on the right side, we have 0 hydrogen atoms in CuSO4. To balance the hydrogen atoms, we can place a coefficient of 2 in front of CuSO4:

? + ? = 2CuSO4 + H2O

Next, let's balance the sulfur (S) atoms. On the left side, we have 1 sulfur atom in H2O, and on the right side, we have 2 sulfur atoms in 2CuSO4. To balance the sulfur atoms, we can place a coefficient of 2 in front of H2O:

? + ? = 2CuSO4 + 2H2O

The equation is now balanced.

4) H2CO3 = H2O + CO2 To balance this equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

Let's start by balancing the hydrogen (H) atoms. On the left side, we have 2 hydrogen atoms in H2CO3, and on the right side, we have 2 hydrogen atoms in H2O. The hydrogen atoms are already balanced.

Next, let's balance the carbon (C) atoms. On the left side, we have 1 carbon atom in H2CO3, and on the right side, we have 1 carbon atom in CO2. The carbon atoms are already balanced.

Finally, let's balance the oxygen (O) atoms. On the left side, we have 3 oxygen atoms in H2CO3, and on the right side, we have 1 oxygen atom in H2O and 2 oxygen atoms in CO2. To balance the oxygen atoms, we can place a coefficient of 3 in front of H2O:

H2CO3 = 3H2O + CO2

The equation is now balanced.