Question

Определить валентность и степень окисления Ba3(PO4)2

Answer 1

Ортофосфат бария - Ba₃(PO₄)₂
Валентность: бария=2
                         фосфора=5
                          кислорода=2
Степень окисления:  
                         бария +2
                         фосфора +5
                          кислорода -2
Ba₃⁺²(P⁺⁵O₄⁻²)₂

Answer 2

Ва- валентность 2, со +2
Р- валентность 5. со +5
О- валентность 2. со -2

Answer 3

Valence and Oxidation State of Ba3(PO4)2

The compound Ba3(PO4)2 consists of barium ions (Ba2+) and phosphate ions (PO43-). To determine the valence and oxidation state of each element in the compound, we need to consider the charges of the ions involved.

- Barium (Ba) is an alkaline earth metal and typically forms Ba2+ ions. - Phosphate (PO43-) is a polyatomic ion consisting of one phosphorus atom and four oxygen atoms. The overall charge of the phosphate ion is -3.

Based on this information, we can determine the valence and oxidation state as follows:

- The valence of barium (Ba) is +2 since it forms Ba2+ ions. - The valence of phosphorus (P) in phosphate (PO43-) is +5 since the overall charge of the phosphate ion is -3.

Therefore, in the compound Ba3(PO4)2, the valence of barium (Ba) is +2, and the valence of phosphorus (P) is +5.

Please note that the valence and oxidation state of an element can vary depending on the compound it is present in. The valence and oxidation state mentioned here are specific to the compound Ba3(PO4)2.